Oracle 切割字符查询

select *  from view_psbaseinfo where DECODE('410782001125,411100000043',              '',              NULL,              '410782001125,411100000043') IS NULL    or PSCODE in       (SELECT REGEXP_SUBSTR('410782001125,411100000043', '[^,]+', 1, LEVEL) AS PSCODE          FROM DUAL        CONNECT BY LEVEL <=                   LENGTH('410782001125,411100000043') + 1 -                   LENGTH(REPLACE('410782001125,411100000043', ',', '')));